An Experiment To Investigate The Lateral Displacement Of A Ray Of Light Through A Rectangular Block Of A Transparent Material.

3426 words - 14 pages

PLANNING: -Title: - An Experiment to investigate the lateral displacement of a ray of light through a rectangular block of a transparent material.Aim: - To investigate the lateral displacement for different angles and how the displacement depends on the angle of incidence when a ray of light enters the Perspex block.Scientific Background: -Refraction occurs when the speed changes when the lights travels from one medium to another medium. If the light travels from a medium to a denser medium, the light slows down and consequently is refracted towards the normal. If the light travels from one medium to a less dense medium, the speed increases and as a result, the light is refracted away from the normal.A measure of how much the light is refracted is the refractive index that can be symbolized to the letter, n which is referred to Snell's law: -When light is refracted, an increase in the angle of incidence, I, produces an increase in the angle of refraction, r. The scientist, Willebrord Snell discovered the link between the two angles where their sines are always in proportion to each other. So, when light passes from one medium into another, the following equation can be formed from Snell' law: - Sin i is constant Sin rAn example of this is illustrated below in the diagram: -V1irDV2(where: i=15o angle of incidencer=10o angle of refractionV1 = speed of light in vacuumV2 = speed of light in mediumD = depth of Perspex block)The refractive index can be found having this information: -Sin 15 = 0.26 = 1.5oSin 10 0.17The formula sin i can also be written as V1Sin r V2A ray of light is bent towards the normal when it enters a glass block and away when it leaves the glass block. The ray leaving the block is parallel to the ray entering the block but is displaced to one side as shown below in the diagram: Angle of incidenceLight RayDEmergent RaydThe significance of d (lateral displacement): -For a thin lens, the depth (D) is too small, therefore it can be ignored, so we can say that a ray of light passing through the center of a thin lens is not displaced. For a thick lens, however, the lateral displacement is significant and must be taken into account. Therefore, an investigation of d is important for a thicker lens. The below diagram distinguishes the difference between a thin and thick lens: -40ortoo smallCalculate r: -n = sin isin r bigger and clearer to read1.5 = sin 40sin rr = 25.4oPrediction: -The first predication was that the lateral displacement would be proportional to the angle of incidence. The results (see later) proved that this prediction was not correct. A second prediction was then made that the lateral displacement would be directly proportional to sin (i-r).cos r(i - r)iArD DCO BFrom this diagram, all the relevant angles and lines have been labeled that will enable me to justify my prediction. A straight-line graph through (0,0) would verify the prediction. Using the diagram...

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