1094 words - 4 pages

As you begin the course of geometry students are generally familiarized with frequently used formulas in mathematics. These formulas include finding the perimeter and area of two-dimensional figures and finding the volume and surface area of three-dimensional figures. For every diverse shape there is a related formula for finding its perimeter, area, volume, or surface area. Therefore, we will only focus on four formulas for four singular shapes or figures. We will find the perimeter of a square, the area of a triangle, the volume of a right circular cylinder and the total surface area of a sphere.

The first formula will correspond to finding the perimeter of a square. For the following formula P will stand for the perimeter and s will represent the side length of the square. The perimeter of a square is found by multiplying four by the side length of the square. Thus, the formula would be P=4s. The motive that the four is in the formula is because a square has four sides. Now let’s use an example, if a square has a side length of 4 inches on every of its four sides the formula would look like this P= 4*4. When this is multiplied together the perimeter would be 16 inches. Visually it would look like this:

P= 4s

P= 4*4

P=16 in

With his in mind we can move to the next formula, which would be to find the area of a triangle. I n the following equation A will symbolize the area of the triangle, b will represent the base and h will be the height. Consequently, to find the area you would multiply one half by the base and then multiply this by the height. For instance, if there is a triangle with a base of eight inches and a height of six inches you would have to multiply one half by the eight inches...

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